PUNJAB NEWS ONLINE: PSEB CLASS 8 MATHEMATICS SOLVED QUESTION PAPER 2026

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CLASS VIII
MATHEMATICS
(Punjabi, Hindi and English Versions)
(Morning Session)

Time allowed : 3 Hours Maximum Marks : 80

(ENGLISH VERSION)

Note :

(i) You must write the subject-code / paper-code 808 in the box provided on the title page of your answer book.

(ii) Make sure that answer book contains 16 pages (including title page) and are properly serialized as soon as you receive it.

(iii) Questions attempted after leaving blank page/s in the answer-book would not be evaluated.

(iv) All Questions are compulsory.

(v) Part-A will have question number 1 carries 20(i-xx) Multiple Choice Questions of 1-1 mark each.

(vi) Part-B have questions from 2 to 8 each of two marks.

(vii) Part-C have questions from 9 to 15 each of 4 marks and there is internal choice in any three questions.

(viii) Part-D have questions from 16 to 18 each of 6 marks and there is internal choice in all questions.

(ix) Questions related to geometry should be solved by drawing appropriate diagram.

(x) Use of calculator is not allowed.

(xi) Graph paper is attached with the question paper.

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PART – A

Select the correct option from the following questions. Each question is of 1 mark :

(i) If length of one diagonal of rectangle is 6 cm, what is the length of other diagonal?

(a) 3 cm
(b) 6 cm
(c) 12 cm
(d) 4 cm

(ii) The Number of zeroes in the square of 600 will be:

(a) 1
(b) 2
(c) 3
(d) 4

(iii) If side of a rectangle are 2ab and 3bc respectively, then its area is:

(a) 6abc
(b) 6ab²c
(c) 2ab + 3bc
(d) 6 + ab + bc

(iv) (3² + 4²)⁰ = __________ ?

(a) 2
(b) 25
(c) 1
(d) 7

(v) If x and y are in inverse proportion then which of the following is true?

(a) xy = k
(b) x/y = k
(c) x + y = k
(d) x − y = k

(vi) (4x² − 8x) ÷ (4x²) = __________

(a) −1 + 2x
(b) 2/x
(c) −1 + 2/x
(d) 2x

(vii) If the edge of cube is doubled then what will happen to its surface area :

(a) 2 times
(b) 4 times
(c) 3 times
(d) Half

(viii) The additive identity of 2/3 is?

(a) 0
(b) −2/3
(c) −2/3
(d) 3/2

(ix) What is the probability of getting a head in tossing of coin?

(a) 1/3
(b) 2/3
(c) 1
(d) 1/2

(x) A perfect cube ends with digit 2. What will be one digit of its cube root?

(a) 4
(b) 2
(c) 6
(d) 8

(xi) Usual form of number 1.6 × 10⁴ is __________ ?

(a) 1600
(b) 16000
(c) 160000
(d) 1.60000

(xii) If 4x = 8, then x = __________ ?

(a) 2
(b) 4
(c) 12
(d) 8

(xiii) Identify coefficient of y in 7y − 5.

(a) 7
(b) −5
(c) 5
(d) 12

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PSEB CLASS 8 MATHEMATICS QUESTION PAPER SOLVED 2026 ( PUNJABI MEDIUM)

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(xiv) For rational numbers x, y and z which of the following is not true?

(a) X × X = Y × X
(b) X × (Y − Z) = X × Y − X × Z
(c) X − Y = Y − X
(d) X × (Y × Z) = (X × Y) × Z

(xv) Discount is calculated on :

(a) S.P.
(b) M.P.
(c) C.P.
(d) None of these

(xvi) The coordinates of origin are __________ .

(a) (1, 0)
(b) (0, 1)
(c) (2, 2)
(d) (0, 0)

(xvii) What will be volume of a cuboid with dimensions 4m × 2.5m × 2m?

(a) 200 m²
(b) 20 m²
(c) 200 m³
(d) 20 m³

(xviii) Sum of adjacent angles in a parallelogram is __________ .

(a) 90°
(b) 180°
(c) 360°
(d) 100°

(xix) Common factor of 5a²b and 9xy² is :

(a) 1
(b) 0
(c) abxy
(d) ax

(xx) Which of the following cannot be a perfect square :

(a) 625
(b) 728
(c) 729
(d) 144

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PART – B

In this part each question is of 2 marks.

Find the smallest number by which 2187 must be divided to obtain a perfect cube.
Simplify 5² × 5⁻³ × 5⁶ and express the result in power notation with positive exponent.
Factorise : x² + xy + 6x + 6y
Write the reciprocal of 3 × (−7/9).
The diagonals of rhombus are 7.5 cm and 12 cm. Find its area.
A book marked at ₹ 791 is sold for ₹ 678. Find discount and discount percentage.
One letter is selected from English alphabet. What is the probability that it is a vowel?

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PART – C

In this part each question is of 4 marks.

Using factor method, divide (x² − x − 42) by (x + 6).
Using suitable identity find the value of 61² − 39².
A gardener has 1100 plant. He wants to plant these in such a way that number of rows and number of columns remains same. Find the minimum number of plants he need more for this.
Preet is 6 year older than Abdul. Six year ago Preet’s age was four times Abdul’s age. Find their present ages.

Solve the equation : 15(a − 4) − 2(a − 9) + 5(a + 6) = 0.

Draw the graph for the value given in table below :

Side of square (in cm) : 3, 5, 6, 8
Perimeter (in cm) : 12, 20, 24, 32

Picture of bacteria enlarged 60000 times attains a length of 3 cm. What is the length of bacteria if it is enlarged 10000 times only.

A company requires 36 machines to make a product in 54 days. How many machines would be required to make the same product in 81 days.

In the given figure PQRS is a rhombus, find x and y.

Two adjacent angles of a parallelogram are in the ratio 3 : 7. Find the measure of all the angles.

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PART – D

In this part each question is of 6 marks.

Population of a town is 1,50,000. The annual birth rate is 5% and mortality rate is 3%. Find the population of town after 2 years.

From a class of 60 students, 40% students like chess, 15% like carrom and remaining students like other games. Find the number of students who like carrom, chess and other games.

A road roller takes 950 complete revolutions to move once over to level a road. Find the area of road levelled if the diameter of road roller is 48 cm and length is 1 m.

Find the area of rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonal is 8 cm. Find the length of other diagonal.

The marks obtained by 40 students of class VIII in an examination are given below :

18, 8, 12, 6, 8, 16, 12, 5, 23, 16, 2, 23, 7, 12, 20, 16, 9, 7, 5, 6, 5, 3, 13, 21, 13, 20, 15, 7, 1, 21, 20, 18, 13, 23, 15, 18, 7, 17, 16, 3

Prepare a frequency distribution using one of the class as 15–20. Draw histogram also.

The following data represents the expenditure of a family in different items :

Item : Food, Clothing, Rent, Education, Others
Expenditure (in ₹) : 4000, 2000, 1500, 1500, 1000

Represent the above data by Pie Chart.

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ANSWER KEY
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PART – A (1 × 20 = 20)

(i) b
(ii) d
(iii) b
(iv) c
(v) a
(vi) c
(vii) b
(viii) a
(ix) d
(x) d
(xi) b
(xii) a
(xiii) a
(xiv) c
(xv) b
(xvi) d
(xvii) d
(xviii) b
(xix) a
(xx) b

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PART – B

1
5⁵
(x + 6)(x + y)
−3/7
45 cm²
Discount = ₹113
Discount % ≈ 14.29%
5/26

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PART – C

Quotient = x − 7
2400
56 plants
Preet = 18 years
Abdul = 12 years

OR
a = 3

Straight line graph (linear relation)
0.5 cm

OR
24 machines

(As per figure values)

OR
Angles = 54°, 126°, 54°, 126°

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PART – D

Population after 2 years = 1,56,060

OR
Chess = 24
Carrom = 9
Others = 27

Area ≈ 14,326.08 m²

OR
Other diagonal = 6 cm

(Frequency table & histogram based on data)

OR
Pie chart angles:
Food = 144°
Clothing = 72°
Rent = 54°
Education = 54°
Others = 36°

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PART – A (Objective Answers)
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(i) b — Diagonals of rectangle are equal.
(ii) d — 600² = 360000 (4 zeroes).
(iii) b — Area = 2ab × 3bc = 6ab²c.
(iv) c — (3²+4²)⁰ = 25⁰ = 1.
(v) a — Inverse proportion ⇒ xy = k.
(vi) c — (4x²−8x)/4x² = 1 − 2/x.
(vii) b — Surface area becomes 4 times.
(viii) a — Additive identity = 0.
(ix) d — 1 favourable / 2 outcomes = 1/2.
(x) d — Cube ending in 2 ⇒ root ends in 8.
(xi) b — 1.6 × 10⁴ = 16000.
(xii) a — 4x = 8 ⇒ x = 2.
(xiii) a — Coefficient of y = 7.
(xiv) c — x − y ≠ y − x.
(xv) b — Discount calculated on M.P.
(xvi) d — Origin = (0,0).
(xvii) d — Volume = 4×2.5×2 = 20 m³.
(xviii) b — Adjacent angles = 180°.
(xix) a — No common variable ⇒ 1.
(xx) b — 728 not perfect square.

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PART – B (2 Marks Each)
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2187 = 3⁷
For perfect cube exponent must be multiple of 3.
Divide by 3 ⇒ 3⁶ (perfect cube).
Answer: 1
5² × 5⁻³ × 5⁶ = 5^(2−3+6) = 5⁵
x² + xy + 6x + 6y
= x(x+y) + 6(x+y)
= (x+6)(x+y)
3 × (−7/9) = −7/3
Reciprocal = −3/7
Area of rhombus = ½ × d₁ × d₂
= ½ × 7.5 × 12 = 45 cm²
Discount = 791 − 678 = ₹113
Discount % = (113/791)×100 ≈ 14.29%
Total letters = 26
Vowels = 5
Probability = 5/26

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PART – C (4 Marks Each)
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x² − x − 42
= (x − 7)(x + 6)
Dividing by (x+6) ⇒ Quotient = x − 7
61² − 39²
= (61+39)(61−39)
= 100 × 22 = 2200
√1100 ≈ 33
33² = 1089
Next square 34² = 1156
Plants needed = 1156 − 1100 = 56
Let Abdul = x
Preet = x+6
6 years ago: (x+6−6)=x and (x−6)
x = 4(x−6)
x = 4x−24
3x = 24
x = 8
Abdul = 8
Preet = 14